Speed, Time, and Distance questions are foundational in quantitative aptitude exams, often determining time management and problem-solving speed.
This topic is crucial because it tests mathematical skills and evaluates a candidate’s logical thinking and ability to apply formulas effectively under pressure.
Key Formulas for Speed, Distance, and Time
Basic Formulas for Speed, Distance, and Time:
- Speed = Distance / Time
- Distance = Speed × Time
- Time = Distance / Speed
These formulas can be remembered using a simple acronym DST where D stands for Distance, S for Speed, and T for Time, and can be visualized as below:

Unit Conversion Tips
Here is a table to convert various units.
From | To | Multiplied By | Example |
|---|---|---|---|
km/h | m/s | 5/18 | 90 km/h × 5/18 = 25 m/s |
m/s | km/h | 18/5 | 15 m/s × 18/5 = 54 km/h |
miles | km | 8/5 | 10 miles × 8/5 = 16 km |
km | miles | 5/8 | 10 km × 5/8 = 6.25 miles |
Shortcut Tricks for Speed Distance and Time Questions
Average Speed for Varying Distances
Formula:
Average Speed = Total Distance/Total Time
When to Use: This formula is helpful when a journey consists of different distances covered at different speeds.
Average Speed for Equal Distances at Different Speeds
Formula:
Average Speed = (2 × Speed 1 × Speed 2)/(Speed 1 + Speed 2)
When to Use: Use this formula when covering equal distances at two different speeds, such as going to a location at one speed and returning at another.
Relative Speed
Relative speed helps understand the effective speed between two moving objects, useful for solving problems involving trains, cars, or boats.
- Same Direction:
- Relative Speed = Difference of Speeds
- Example: Two trains moving at 80 km/h and 60 km/h in the same direction:
- Relative Speed = 80 - 60 = 20 km/h
- Relative Speed = Difference of Speeds
- Opposite Directions:
- Relative Speed = Sum of Speeds
- Example: Two trains moving at 80 km/h and 60 km/h toward each other:
- Relative Speed = 80 + 60 = 140 km/h
- Relative Speed = Sum of Speeds
Time to Meet or Overtake
- Meeting Time:
- Time = Distance ÷ Relative Speed
- Example: Two cars 300 km apart moving toward each other at 50 km/h and 70 km/h:
- Relative Speed = 50 + 70 = 120 km/h
- Time = 300 ÷ 120 = 2.5 hours
- Overtaking Time:
- Time = Distance ÷ Relative Speed
- Example: A faster car overtaking a slower car 100 meters ahead, with speeds of 20 m/s and 15 m/s respectively:
- Relative Speed = 20 - 15 = 5 m/s
- Time = 100 ÷ 5 = 20 seconds
Train Problems
Passing a Stationary Object: When a train passes a stationary object, the distance covered is equal to the length of the train.
Formula: Time = Length of Train ÷ Speed
Example: A train 275 meters long is moving at a speed of 66 km/h. How long will it take for the train to pass a stationary signal post?
Length of Train = 275 meters
Speed = 68 km/h
- Convert speed to meters per second:
- Speed = 68 × (5/18) ≈ 18.89 m/s
- Time = Length of Train ÷ Speed
- 275 ÷ 18.89 ≈ 14. 56 seconds
The train will take approximately 14.56 seconds to pass the stationary signal post completely.
Train Passing a Platform: When a train passes a platform, the distance covered is the sum of the lengths of the train and the platform.
Formula: Time = (Length of Train + Length of Platform) ÷ Speed
Example: A train 225 meters long is traveling at a speed of 60 km/h. How long will it take for the train to completely pass a platform that is 180 meters long?
Length of Train = 225 meters
Length of Platform = 180 meters
Speed = 60km/h
- Convert Speed to Meters per Second:
- Speed = 60 × (5/18) = 16.67 m
- Calculate Total Distance to Pass the Platform:
- Total Distance = Length of Train + Length of Platform
- Total Distance = 225 meters + 180 meters = 405 meters
- Calculate Time to Pass the Platform:
- Time = Total Distance ÷ Speed
- Time = 405 meters ÷ 16.67 m/s ≈ 24.3 seconds
The train will take approximately 24.3 seconds to pass the stationary signal post completely.
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