Binomial Expansion Formulas

Last Updated : 23 Jul, 2025

Binomial expansion formula is a formula that is used to solve binomial expressions. A binomial is an algebraic expression with two terms. For example, x + y, x - a, etc are binomials.

In this article, we have covered the Binomial Expansion definition, formulas, and others in detail.

Binomial Expansion

An algebraic expression containing two terms is called a binomial expression. Example: (x + y), (2x - 3y), (x + (3/x)). The general form of the binomial expression is (x + a) and the expansion of (x + a)n, n ∈ N is called the binomial expansion. The binomial expansion provides the expansion for the powers of binomial expression.

What Are Binomial Expansion Formula?

Binomial expansion formulas are formulas that are used to solve algebraic expressions which are not easily solved using algebraic identities. Binomial Expansion Formulas are categorized into two categories that are:

  • Binomial Expansion Formula of Natural Powers
  • Binomial Expansion Formula of Rational Powers

Binomial Expansion Formula of Natural Powers

Binomial expansion formula for the expansion of (x + y)n where 'n' is a natural number is added below:

(x + a)n = nC0xna0 + nC1xn-1a1 + nC2xn-2a2 + .........+ nCr xn-rar + ........ + nCn-1x1an-1 + nCnx0an

(x + a)n = nCr xn-rar 

Proof:

Proof of binomial expansion using the principle of mathematical induction on n.

Let X(n) be : (x + a)n = nC0xna0 + nC1xn-1a1 + nC2xn-2a2 + .........+ nCr xn-rar + ........ + nCn-1x1an-1 +nCnx0an

Step I:

To prove: X(1) : (x + a)1 =1C0x1a0 + 1C1x0a1

We know that : (x + a)1 = x + a = 1C0x1a0 + 1C1x0a1

therefore, X(1) is true

Step II:

Let X(m) be true. Then,

(x + a)m = mC0xma0 + mC1xm-1a1 + mC2xm-2a2 + .........+ mCm-1x1am-1 +mCmx0am    ------------(1)

To prove: X(m+1) is true. i.e. 

(x + a)m+1 = m+1C0xm+1a0 + m+1C1xma1 + m+1C2xm-1a2 + .........+ m+1Cmx1am +m+1Cm+1x0am+1

Proof: (x + a)m+1 = (x + a)(x + a)m

= (x + a)[mC0xma0 + mC1xm-1a1 + mC2xm-2a2 + .........+mCrxm-rar+ mCm-1x1am-1 +mCmx0am]

= mC0xm+1a0 + (mC1 + mC0)xma1 + (mC2 + mC1)xm-1a2 + ... +(mCr + mCr-1)xm-r+1ar + ... + (mCm-1 + mCm)x1am + mCmam+1

[Since, mCr-1 + mCr = m+1Cr , r = 1, 2, 3....., m]

= m+1C0xm+1a0 + m+1C1xma1 + m+1C2xm-1a2 + .........+ m+1Cmx1am + m+1Cm+1x0am+1

X(m + 1) is true.

X(m) is true ⇒ X(m + 1) is true

Binomial Expansion Formula of Rational Powers

Binomial expansion formula for the expansion of (1 + x)n where 'n' is a rational number is added below:

(1 + x)n = 1 + n x + [n(n - 1)/2!] x+  [n(n - 1)(n - 2)/3!]  x3 + ... 

Binomial Expansion Formula Characterstics

Various characteristics of binomial expansion formulas are:

  • In Binomial expansion, r can have values from 0 to n, the total number of terms in the expansion is (n+1).
  • Sum of indices of x and a in each term is n.
  • Since, nCr = nCn-r , for r = 0,1,2......,n . Hence, the coefficients of terms equidistant from the starting and end are equal. So such coefficients are known as binomial coefficients.
  • (x-a)n =\sum_{r=0}^{n}     (-1)r nCrxn-ra  In the expansion of (x-a)n we have alternate positive and negative terms and sign of last term depends on the value of n (odd or even).
  • Coefficient of (r+1)th term or xr in the expansion of (1 + x)n is nCr.
  • (x + a)n + (x - a)n = 2[nC0xna0 + nC2xn-2a2 + .......] and (x + a)n - (x - a)n = 2[nC1xn-1a1 + nC3xn-3a3 + .......] 
  • In the binomial expansion of (x + a)n, the general term is given by Tr+1 = nCrxn-rar
  • In the binomial expansion of (x - a)n, the general term is given by Tr+1 = (-1)r nCrxn-rar
  • Binomial expansion of (x + a)n contains (n + 1) terms. Therefore, if n is even, then ((n/2) + 1)th term is the middle term and if n is odd, then ((n + 1)/2)th and ((n + 3)/2)th terms are the two middle terms.  

Different values of n have a different number of terms:

  n(x + a)n + (x - a)n(x + a)n - (x - a)n
odd       (n+1)/2       (n+1)/2
even       (n/2)+1        (n/2)

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Examples Using Binomial Expansion Formulas

Example 1: Find the number of terms in the expansions of the following :

(i) (9x - y)9

(ii) (1 +7x)9 + (1 - 7x)9

(iii) (1 + 2x + x2)20

Solution: 

(i)

In the expansion of (x + a)n the number of terms is (n+1)

Hence, in the expansion of (9x - y)9 the number of terms is 10

(ii)

In the expansion of (x + a)n + (x - a)n the number of terms is (n+1)/2 if n is odd.

So number of terms in the expansion of (1 + 7x)9 + (1 - 7x)9

= (10/2) = 5   

(iii)

(1 + 2x + x2)20

= [(1 + x)2]20

= (1 + x)40

Hence, number of terms = 41

Example 2: Expand (3x + 8)4

Solution: 

According to binomial expansion :

(3x + 8)4 = 4C0 (3x)4 (8)0 +  4C1 (3x)3 (8)1 + 4C2 (3x)2 (8)2 +  4C3 (3x)1 (8)3 4C4 (3x)0 (8)4

= (3x)4 + 4.(3x)3.8 + 6.(3x)2.64 +4.(3x).512 + 4096

= 12x4 + 864 x3 + 3456 x2 + 6144 x + 4096

Example 3: Expand (2x - 1)5

Solution: 

According to binomial expansion :

(2x - 1)5 = (2x + (-1))5 = 5C0 (2x)5 (-1)0 5C1 (2x)4 (-1)1 + 5C2 (2x)3 (-1)2 +  5C3 (2x)2 (-1)3 +  5C4 (2x)1 (-1)4 + 5C5 (2x)0(-1)5

= 32x5 - 5.16x4 + 10.8x3 - 10.4x2 + 10x - 1

= 32x5 - 80x4 + 80x3 - 40x2 + 10x - 1

Example 4: Expand (1 + x + x2)3

Solution: 

Let, y = x + x2

(1 + x + x2)3 = (1 + y)3 = 3C0 (1)3 (y)0 +  3C1 (1)2 (y)1 + 3C2 (1)1 (y)2 +  3C3 (1)0 (y)3 

= 1 + 3y + 3y2 + y3

= 1 + 3(x + x2) + 3(x + x2)2 + (x + x2)3 = 1 + 3x + 3x2 + 3(x2 + x4 + 2x3) + (x3 + x6 + 3x4 + 3x5)

= 1 + 3x +  3x2 + 3x2 + 3x4 + 6x3 + x3 + x6 + 3x4 + 3x

= 1 + 3x + 6x2 + 7x3 + 6x4 + 3x5 + x6

Example 5: Find (a + b)4 - (a - b)4. Hence, evaluate (√3 + √2)4 - (√3 - √2)4.

Solution: 

(a + b)4 - (a - b)4 = 2.[4C1a3b1 + 4C3a1b3] = 2.[4a3b1 + 4a1b3] = 8a3b1 + 8a1b3 

Put a = √3 and b = √2 

(√3 + √2)4 - (√3 - √2)4 = 8.(√3)3(√2) + 8.(√3)(√2)3 = 24√6 + 16√6 = 40√6 

Example 6: Find the 10th term in the binomial expansion of (4x2 + 1/x)11.

Solution: 

In the binomial expansion of (x + a)n , (r+1)th term is given by Tr+1 = nCrxn-rar

In the expansion of (4x2 + 1/x)11 , [n = 11, r = 9, x = 4x2, a = 1/x]

T10 = T9+1 = 11C9 (4x2)11-9 (1/x)9 = 55.(16x4).(1/x9) = 880/x5

Example 7: Find the middle term in the expansion of [(4/3)x2 - (3/4x)]20.

Solution: 

Here, n = 20 (even)

[(20/2) + 1]th term i.e. 11th term is the middle term.

Hence, the middle term = T11 = T10+1 = 20C10.[(4x2/3)]20-10. [-(3/4x)]10 = 20C10.x10

Summary

Binomial Expansion is a mathematical technique used to expand expressions that are raised to a power, where the expression is a binomial (an algebraic expression with two terms). The binomial expansion of (x+a)n allows us to express it as a sum of terms involving different powers of x and a with coefficients known as binomial coefficients.

Practice Problems on Binomial Expansion Formulas

Question 1: Find the number of terms in the expansion of (2x + y)7

Question 2: Expand (5x - 2)6 and simplify the expression.

Question 3: Expand (1 + 1/x)8 up to the term involving x2

Question 4: Find the 8th term in the expansion of (2x + 3)9.

Question 5: Determine the middle term in the expansion of (x - 1/x)10

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