Find N Arithmetic Means between A and B

Given three integers A, B and N the task is to find N Arithmetic means between A and B. We basically need to insert N terms in an Arithmetic progression. where A and B are first and last terms. Examples:

Input : A = 20 B = 32 N = 5
Output : 22 24 26 28 30
The Arithmetic progression series as 
20 22 24 26 28 30 32 

Input : A = 5  B = 35  N = 5
Output : 10 15 20 25 30

Approach : Let A₁, A₂, A₃, A₄......A_n be N Arithmetic Means between two given numbers A and B . Then A, A₁, A₂ ..... A_n, B will be in Arithmetic Progression . Now B = (N+2)^th term of the Arithmetic progression . So : Finding the (N+2)^th term of the Arithmetic progression Series where d is the Common Difference B = A + (N + 2 - 1)d B - A = (N + 1)d So the Common Difference d is given by. d = (B - A) / (N + 1) So now we have the value of A and the value of the common difference(d), now we can find all the N Arithmetic Means between A and B. 

// C++ program to find n arithmetic 
// means between A and B
#include <bits/stdc++.h>
using namespace std;
 
// Prints N arithmetic means between
// A and B.
void printAMeans(int A, int B, int N)
{
    // calculate common difference(d)
    float d = (float)(B - A) / (N + 1);
     
    // for finding N the arithmetic 
    // mean between A and B
    for (int i = 1; i <= N; i++) 
        cout << (A + i * d) <<" ";    
}
 
// Driver code to test above 
int main()
{
    int A = 20, B = 32, N = 5;
    printAMeans(A, B, N);    
    return 0;
}

// java program to illustrate
// n arithmetic mean between 
// A and B
import java.io.*;
import java.lang.*;
import java.util.*;
 
public class GFG {
 
    // insert function for calculating the means
    static void printAMeans(int A, int B, int N)
    {       
        // Finding the value of d Common difference
        float d = (float)(B - A) / (N + 1);
                            
        // for finding N the Arithmetic 
        // mean between A and B
        for (int i = 1; i <= N; i++) 
          System.out.print((A + i * d) + " ");
         
    }
 
    // Driver code
    public static void main(String args[])
    {
        int A = 20, B = 32, N = 5;
        printAMeans(A, B, N);
    }
}

# Python3 program to find n arithmetic
# means between A and B

# Prints N arithmetic means 
# between A and B.
def printAMeans(A, B, N):

    # Calculate common difference(d)
    d = (B - A) / (N + 1)
    
    # For finding N the arithmetic 
    # mean between A and B
    for i in range(1, N + 1): 
        print(int(A + i * d), end = " ") 

# Driver code
A = 20; B = 32; N = 5
printAMeans(A, B, N) 

# This code is contributed by Smitha Dinesh Semwal

// C# program to illustrate 
// n arithmetic mean between  
// A and B 
using System; 
  
public class GFG { 
  
    // insert function for calculating the means 
    static void printAMeans(int A, int B, int N) 
    {      
        // Finding the value of d Common difference 
        float d = (float)(B - A) / (N + 1); 
                              
        // for finding N the Arithmetic  
        // mean between A and B 
        for (int i = 1; i <= N; i++)  
        Console.Write((A + i * d) + " "); 
          
    } 
  
    // Driver code 
    public static void Main() 
    { 
        int A = 20, B = 32, N = 5; 
        printAMeans(A, B, N); 
    } 
} 
// Contributed by vt_m 

<?php
// PHP program to find n arithmetic 
// means between A and B

// Prints N arithmetic means 
// between A and B.
function printAMeans($A, $B, $N)
{
    
    // calculate common
    // difference(d)
    $d = ($B - $A) / ($N + 1);
    
    // for finding N the arithmetic 
    // mean between A and B
    for ($i = 1; $i <= $N; $i++) 
        echo ($A + $i * $d) ," "; 
}

    // Driver Code 
    $A = 20; $B = 32; 
    $N = 5;
    printAMeans($A, $B, $N);
    
// This code is Contributed by vt_m.
?>

<script>

// JavaScript program to find n arithmetic
// means between A and B

// Prints N arithmetic means 
// between A and B.
function printAMeans(A, B, N){

    // Calculate common difference(d)
    let d = (B - A) / (N + 1)
    
    // For finding N the arithmetic 
    // mean between A and B
    for(let i = 1; i < N + 1; i++) 
        document.write(Math.floor(A + i * d)," ") 
}

// Driver code
let A = 20, B = 32, N = 5;
printAMeans(A, B, N) 

// This code is contributed by Shinjanpatra

</script>

22 24 26 28 30

 Time Complexity : O(N) ,where N is the number of terms             

 Space Complexity : O(1), since no extra space has been taken.