C Language | Set 5

int f(int x, int *py, int **ppz)
{ 
  int y, z; 
  **ppz += 1;  
   z  = **ppz; 
  *py += 2; 
   y = *py;
   x += 3;
   return x + y + z;
}

void main()
{
   int c, *b, **a;
   c = 4; 
   b = &c;
   a = &b;  
   printf( "%d", f(c,b,a));
   getchar();
}

/* Explanation for the answer */

  /*below line changes value of c to 5. Note that x remains unaffected 
    by this change as x is a copy of c and address of x is different from c*/
  **ppz += 1 

  /* z is changed to 5*/
  z  = **ppz;

  /* changes c to 7, x is not changed */ 
  *py += 2;

   /* y is changed to 7*/
  y = *py;   

  /* x is incremented by 3 */
   x += 3;   

  /* return 7 + 7 + 5*/
  return x + y + z; 

void reverse(void)
 {
  int c;
  if (?1) reverse() ;
  ?2
}
main()
{
  printf ("Enter Text ") ;
  printf ("\n") ;
  reverse();
  printf ("\n") ;
}

void reverse(void); /* function prototype */

void reverse(void)
 {
  int c;
  if (((c = getchar()) != '\n')) 
    reverse();  
  putchar(c);
}
main()
{
  printf ("Enter Text ") ;
  printf ("\n") ;
  reverse();
  printf ("\n") ;
  getchar();
}

int f1(int n)
{
  if(n == 0 || n == 1)
    return n;
  else
    return (2*f1(n-1) + 3*f1(n-2));
}

int f2(int n)
{
  int i;
  int X[N], Y[N], Z[N] ;
  X[0] = Y[0] = Z[0] = 0;
  X[1] = 1; Y[1] = 2; Z[1] = 3;
  for(i = 2; i <= n; i++)
  {
    X[i] = Y[i-1] + Z[i-2];
    Y[i] = 2*X[i];
    Z[i] = 3*X[i];
  }
  return X[n] ;
}