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28 Mathieu Functions and Hill’s EquationMathieu Functions of Noninteger Order

§28.15 Expansions for Small q

Contents
  1. §28.15(i) Eigenvalues \lambda_{\nu}\left(q\right)
  2. §28.15(ii) Solutions \operatorname{me}_{\nu}(z,q)

§28.15(i) Eigenvalues \lambda_{\nu}\left(q\right)

28.15.1 \lambda_{\nu}\left(q\right)=\nu^{2}+\frac{1}{2(\nu^{2}-1)}q^{2}+\frac{5\nu^{2}%
+7}{32(\nu^{2}-1)^{3}(\nu^{2}-4)}q^{4}+\frac{9\nu^{4}+58\nu^{2}+29}{64(\nu^{2}%
-1)^{5}(\nu^{2}-4)(\nu^{2}-9)}q^{6}+\cdots.

Higher coefficients can be found by equating powers of q in the following continued-fraction equation, with a=\lambda_{\nu}\left(q\right):

28.15.2 a-\nu^{2}-\cfrac{q^{2}}{a-(\nu+2)^{2}-\cfrac{q^{2}}{a-(\nu+4)^{2}-\cdots}}=%
\cfrac{q^{2}}{a-(\nu-2)^{2}-\cfrac{q^{2}}{a-(\nu-4)^{2}-\cdots}}.

§28.15(ii) Solutions \operatorname{me}_{\nu}(z,q)

28.15.3 \operatorname{me}_{\nu}\left(z,q\right)=e^{\mathrm{i}\nu z}-\frac{q}{4}\left(%
\frac{1}{\nu+1}e^{\mathrm{i}(\nu+2)z}-\frac{1}{\nu-1}e^{\mathrm{i}(\nu-2)z}%
\right)+\frac{q^{2}}{32}\left(\frac{1}{(\nu+1)(\nu+2)}e^{\mathrm{i}(\nu+4)z}+%
\frac{1}{(\nu-1)(\nu-2)}e^{\mathrm{i}(\nu-4)z}-\frac{2(\nu^{2}+1)}{(\nu^{2}-1)%
^{2}}e^{\mathrm{i}\nu z}\right)+\cdots;

compare §28.6(ii).