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17 q-Hypergeometric and Related FunctionsProperties

Β§17.2 Calculus

Contents
  1. Β§17.2(i) q-Calculus
  2. Β§17.2(ii) q-Binomial Coefficients
  3. Β§17.2(iii) q-Binomial Theorem
  4. Β§17.2(iv) q-Derivatives
  5. Β§17.2(v) q-Integrals
  6. Β§17.2(vi) Rogers–Ramanujan Identities

Β§17.2(i) q-Calculus

For n=0,1,2,\dots,

17.2.1 \left(a;q\right)_{n}=(1-a)(1-aq)\cdots(1-aq^{n-1}),

For \nu\in\mathbb{C}

17.2.3 \left(a;q\right)_{\nu}=\prod_{j=0}^{\infty}\left(\frac{1-aq^{j}}{1-aq^{\nu+j}}%
\right),

when this product converges.

17.2.4 \left(a;q\right)_{\infty}=\prod_{j=0}^{\infty}(1-aq^{j}),

For properties of the function \mathit{f}\left(q\right)=q^{\ifrac{-1}{24}}\eta\left(\frac{\ln q}{2\pi\mathrm{%
i}}\right)=\left(q;q\right)_{\infty} see Β§27.14. Let q={\mathrm{e}}^{-t} and \hat{q}={\mathrm{e}}^{\ifrac{-4\pi^{2}}{t}}. Then

17.2.6_1 \left(q;q\right)_{\infty}=\sqrt{\frac{2\pi}{t}}\exp\left(-\frac{{\pi}^{2}}{6t}%
+\frac{t}{24}\right)\left(\hat{q};\hat{q}\right)_{\infty},\Re t>0,
17.2.6_2 \left(-q;q\right)_{\infty}=\frac{1}{\sqrt{2}}\exp\left(\frac{{\pi}^{2}}{12t}+%
\frac{t}{24}\right)\left(\hat{q}^{\frac{1}{2}};\hat{q}\right)_{\infty},t>0.

For these and similar results see Apostol (1990, Ch.Β 3) and Katsurada (2003, Β§3). Note that (17.2.6_1) is just (27.14.14) with a=d=0 and -b=c=1.

17.2.8 \frac{\left(a;q^{-1}\right)_{n}}{\left(b;q^{-1}\right)_{n}}=\frac{\left(a^{-1}%
;q\right)_{n}}{\left(b^{-1};q\right)_{n}}\left(\frac{a}{b}\right)^{n},
17.2.10 \frac{\left(a;q\right)_{n}}{\left(b;q\right)_{n}}=\frac{\left(q^{1-n}/a;q%
\right)_{n}}{\left(q^{1-n}/b;q\right)_{n}}\left(\frac{a}{b}\right)^{n},
17.2.12 \frac{\left(aq^{-n};q\right)_{n}}{\left(bq^{-n};q\right)_{n}}=\frac{\left(q/a;%
q\right)_{n}}{\left(q/b;q\right)_{n}}\left(\frac{a}{b}\right)^{n}.

more generally,

17.2.21 \left(a^{2};q^{2}\right)_{n}=\left(a;q\right)_{n}\left(-a;q\right)_{n},
17.2.22 \frac{\left(qa^{\frac{1}{2}},-qa^{\frac{1}{2}};q\right)_{n}}{\left(a^{\frac{1}%
{2}},-a^{\frac{1}{2}};q\right)_{n}}=\frac{\left(aq^{2};q^{2}\right)_{n}}{\left%
(a;q^{2}\right)_{n}}=\frac{1-aq^{2n}}{1-a},

more generally,

17.2.23 \frac{\left(qa^{\frac{1}{k}},q\omega_{k}a^{\frac{1}{k}},\dots,q\omega_{k}^{k-1%
}a^{\frac{1}{k}};q\right)_{n}}{\left(a^{\frac{1}{k}},\omega_{k}a^{\frac{1}{k}}%
,\dots,\omega_{k}^{k-1}a^{\frac{1}{k}};q\right)_{n}}=\frac{\left(aq^{k};q^{k}%
\right)_{n}}{\left(a;q^{k}\right)_{n}}=\frac{1-aq^{kn}}{1-a},

where \omega_{k}={\mathrm{e}}^{2\pi i/k}.

17.2.25 \lim_{\tau\to 0}\frac{\left(a/\tau;q\right)_{n}}{\left(b/\tau;q\right)_{n}}=%
\lim_{\sigma\to\infty}\frac{\left(a\sigma;q\right)_{n}}{\left(b\sigma;q\right)%
_{n}}=\left(\frac{a}{b}\right)^{n},

Β§17.2(ii) q-Binomial Coefficients

17.2.27 \genfrac{[}{]}{0.0pt}{}{n}{m}_{q}=\frac{\left(q;q\right)_{n}}{\left(q;q\right)%
_{m}\left(q;q\right)_{n-m}}\\
=\frac{\left(q^{-n};q\right)_{m}(-1)^{m}q^{nm-\genfrac{(}{)}{0.0pt}{}{m}{2}}}{%
\left(q;q\right)_{m}},

provided that r>s.

Β§17.2(iii) q-Binomial Theorem

In the limit as q\to 1, (17.2.35) reduces to the standard binomial theorem

When n\to\infty in (17.2.35), and when m\to\infty in (17.2.38), the results become convergent infinite series and infinite products (see (17.5.1) and (17.5.4)).

See also Β§26.9(ii).

Β§17.2(iv) q-Derivatives

The q-derivatives of f(z) are defined by

17.2.41 \mathcal{D}_{q}f(z)=\begin{cases}\dfrac{f(z)-f(zq)}{(1-q)z},&z\neq 0,\\
f^{\prime}(0),&z=0,\end{cases}

and

When q\to 1 the q-derivatives converge to the corresponding ordinary derivatives.

Product Rule

17.2.43 \mathcal{D}_{q}(f(z)g(z))=g(z)f^{[1]}(z)+f(zq)g^{[1]}(z).

Leibniz Rule

q-differential equations are considered in Β§17.6(iv).

Β§17.2(v) q-Integrals

If f(x) is continuous at x=0, then

and more generally, \qint_{a}^{b}f(x)\,{\mathrm{d}}_{q}x=\qint_{0}^{b}f(x)\,{\mathrm{d}}_{q}x-%
\qint_{0}^{a}f(x)\,{\mathrm{d}}_{q}x, where

17.2.46 \qint_{0}^{a}f(x)\,{\mathrm{d}}_{q}x=a(1-q)\sum_{j=0}^{\infty}f(aq^{j})q^{j}.

If f(x) is continuous on [0,a], then

Infinite Range

provided that \sum_{j=-\infty}^{\infty}f(q^{j})q^{j} converges.

Β§17.2(vi) Rogers–Ramanujan Identities

17.2.49 1+\sum_{n=1}^{\infty}\frac{q^{n^{2}}}{(1-q)(1-q^{2})\cdots(1-q^{n})}=\prod_{n=%
0}^{\infty}\frac{1}{(1-q^{5n+1})(1-q^{5n+4})},
17.2.50 1+\sum_{n=1}^{\infty}\frac{q^{n^{2}+n}}{(1-q)(1-q^{2})\cdots(1-q^{n})}=\prod_{%
n=0}^{\infty}\frac{1}{(1-q^{5n+2})(1-q^{5n+3})}.

These identities are the first in a large collection of similar results. See Β§17.14.